InterviewSolution
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InterviewSolution
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Number of hydrogen ions present in 10 millionth part of `1.33 cm^(3)` of pure water at `25^(@)C` isA. 6.023 millionB. 60 millionC. 8.01 millionD. 80.23 million |
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Answer» Correct Answer - C Now `[H^(+)]=10^(-7)` mole/litre Now 1000 ml contains `10^(-7)` mole `H^(+)` 1 ml contains `10^(-7)/1000` mole `H^(+)` `1.33xx10^(-7)` ml - contains `1.33xx10^(-17)` 10 million `=10^(-7)` so, `10 "million"^(th)` part of `1.33 cm^(3)=1.33xx10^(-7)` ml so, no. of `H^(+)` ions `=1.33xx10^(-17)xxN_(A)`. |
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