Number of intergal values of x satisfying the inequality `(x^2+6x-7)/( – InterviewSolution

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1.	Number of intergal values of x satisfying the inequality `(x^2+6x-7)/(\|x+2\|\|x+3\|) lt 0 `isA. 5B. 6C. 7D. 8
Answer» Correct Answer - A We have `(x^2+6x-7)/(\|x+2\|\|x+3\|) lt 0 ` Clearly ,` ne -2,-3` Now `x^2+6x-7 lt 0 ` `rArr (x+7)(x-1) lt 0 ` `rArr in (-7,1)-{-3,-2}` So ,intergers are {-6 ,-5 -4,-1,0}

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