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Number of isomers of pt(nh3)2cl2 is a)3 b)4 c)2 d)5 |
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Answer» We have to find the no of isomers of Pt(NH₃)₂Cl₂. solution : Pt(NH₃)₂Cl₂ exists in square planner geometrical shape. there are two ammonia and two chlorine ATTACHING with platinum. so the general form of this compound is MA₂B₂. we know, this TYPE of structure can be shaped into two forms cis and trans. see figure to understand. Therefore no of isomers of Pt(NH₃)₂Cl₂ is two i.e., cis Pt(NH₃)₂Cl₂ and trans Pt(NH₃)₂Cl₂. also read similar questions : Which of the following can't show isomerism ? (1) [NI(NH3)2Cl2] (2) [Ni(en)3] (3) [Pt(NH3)2Cl2] (4) [NA(NH3)4(H20)2] iupac name of pt(nh3)2cl2(no2) |
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