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Number of mole of KMnO4 is required to react completely with 1 mole of Fe2(C2O4)3 in acidic medium is equal to(1) 6/5(2) 1.2(3) 5(4) Both 1 & 2 |
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Answer» Correct option is (A) 6/5 In acidic medium- \(M_n{O_4}^- \longrightarrow Mn^{+2}\) or \(Mn{O_4}^- + 8H^+ + 5e^- \longrightarrow Mn^{+2} + 4H_2O\) ....(i) \([C_2{O_4}^{-2} \longrightarrow 2CO_2 + 2e^-]\) ......(ii) Applying 5 x (ii) + 2 x (i), we get ⇒ \(2Mn{O_4}^- + 16H^+ + 5C_2 {O_4}^{-2} \longrightarrow 10CO_2 + 2Mn^{+2} + 8H_2O\) or \(2KMnO_4 + 8H_2SO_4+ \frac 53 Fe_2(C_2O_4)_3 \longrightarrow 10CO_2 + 2MnSO_4 + K_2SO_4 + \frac 53Fe_2(SO_4)_3\) \(\because \frac 53\) mole Fe2(C2O4)3 react with 2 mole of KMnO4. \(\therefore\) 1 mole of Fe2(C2O4)3 react with = \(\frac 2{5/3}\) mole of KMnO4 \(= \frac{2\times 3}5\) \(= \frac 65\) mole of KMnO4 |
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