Number of molecules in a volume of 4 cm3 of a perfect monoatomic gas a

1.	Number of molecules in a volume of 4 cm3 of a perfect monoatomic gas at some temperature T and at a pressure of 2 cm of mercury is close to ? (Given, mean kinetic energy of a molecule (at T) is 4 × 10–14 erg, g = 980 cm/s2, density of mercury = 13.6 g/cm3)(1) 5.8 × 1018 (2) 4.0 × 1016 (3) 5.8 × 1016 (4) 4.0 × 1018
Answer» Correct answer is (4) 4.0 × 10¹⁸ PV = NkT E = \(\frac{3}{2}\)kT N = \(\frac{3PV}{2E}\) (P = hρg) = 4 x 10¹⁸

Number of molecules in a volume of 4 cm3 of a perfect monoatomic gas at some temperature T and at a pressure of 2 cm of mercury is close to ? (Given, mean kinetic energy of a molecule (at T) is 4 × 10–14 erg, g = 980 cm/s2, density of mercury = 13.6 g/cm3)(1) 5.8 × 1018 (2) 4.0 × 1016 (3) 5.8 × 1016 (4) 4.0 × 1018

Answer»

Correct answer is (4) 4.0 × 10¹⁸

PV = NkT

E = \(\frac{3}{2}\)kT

N = \(\frac{3PV}{2E}\) (P = hρg)

= 4 x 10¹⁸

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