Number of moles of K_(2)Cr_(2)O_(7) that can be reduced by 1 mole of S

1.	Number of moles of K_(2)Cr_(2)O_(7) that can be reduced by 1 mole of Sn^(2+) ions is :
Answer» `1//3` `3//2` `5//6` `6//5` SOLUTION :The redox reaction is : `Cr_(2)O_(7)^(2-)+14H^(+) +3Sn^(2+) to 2Cr^(3+)+7H_(2)O+3Sn^(4+)` `THEREFORE 1 " mole of " Sn^(2+)` will reduce `1//3 " mole of " K_(2)Cr_(2)O_(7)`

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