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Number of moles of `K_2Cr_2O_7` reduced by one mole of `Sn^(2+)` ion isA. `(1)/(3)`B. `3`C. `(1)/(6)`D. 6 |
Answer» Correct Answer - a Eq. of `Cr_2O_7^(2-)=`Eq. of `Sn^(2+)` (`n` factor`=6`) (`n` factor`=6`) ltbr `(1)/(6)` mol. Of `Cr_2O_7^(2-)=(1)/(2)`mol. Of `Sn^(2+)` 1 mol of `Sn^(2+)=(2)/(6)=(1)/(3)` mol. Of `Cr_2O_7^(2-)` |
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