Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will beA. 7.5 molB. 0.2 molC. 0.6 molD. 0.4 mol

Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferro

1.	Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will beA. 7.5 molB. 0.2 molC. 0.6 molD. 0.4 mol
Answer» Correct Answer - C `MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O` `FeC_(2)O_(4)rarrFe^(2+)+C_(2)O_(4)^(2-)` `Fe^(2+)rarrFe^(3+)+e^(-)` `C_(2)O_(4)^(2-)rarr2CO_(2)+2e^(-)` Since one mole of `FeC_(2)O_(4)` loses 3 moles of electrons whole one mole of `MnO_(4)^(-)` accepts five moles of electrons Hence `KMnO_(4)` required to oxidize one mole of `FeC_(2)O_(4)=3//5 = 0.6` mol.

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Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will beA. 7.5 molB. 0.2 molC. 0.6 molD. 0.4 mol

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