Number of moles of MnO_(4)^(-) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

Number of moles of MnO_(4)^(-) required to oxidize one mole of ferrous

1.	Number of moles of MnO_(4)^(-) required to oxidize one mole of ferrous oxalate completely in acidic medium will be
Answer» 7.5 moles 0.2 moles 0.6 moles 0.4 moles Solution :`MnO_(4)^(-)+8H^(+)+5e^(-)(rarrMltn^(2+))+4H_(2)O` `FeC_(2)O_(4)rarrFe^(2+)+C_(2)O_(4)^(23-)` `Fe^(2+)rarrFe^(3+)+e^(-)` `C_(2)O_(4)^(2-)rarr2CO_(2)+2e^(-)` since one mole of `FeC_(2)O_(4)` loses 3 moles of electrons while one mole of `KMnO_(4)` accepts five moles of electrons THEREFORE NUMBER of moles of `KMnO_(4)` required to oxidised one mole of `FeC_(21)O_(4)=3//5 =0.6` mole