Number of moles of oxygen liberated by electrolysis of 90g of waterA. 9 molesB. 4-5 molesC. 2.5molesD. 5 moles.

Number of moles of oxygen liberated by electrolysis of 90g of waterA.

1.	Number of moles of oxygen liberated by electrolysis of 90g of waterA. 9 molesB. 4-5 molesC. 2.5molesD. 5 moles.
Answer» Correct Answer - c Electrolysis of water `2H_(2)Ooverset("Electrolysis")rarr2H_(2)+O_(2)` `therefore 2` mol `H_(2)O=1` mol of `O_(2)` and 5 mol `H_(2)O=(1)/(2)xx5=2.5` mol of `O_(2)`

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Number of moles of oxygen liberated by electrolysis of 90g of waterA. 9 molesB. 4-5 molesC. 2.5molesD. 5 moles.

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