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InterviewSolution
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Number of neutrons present in 1.7g of ammonia is? |
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Answer» In one atom of ammonia,Number of Electrons = 10Number of Protons = 10Number of Neutrons = Mass Number - Atomic Number = 17 - 10 = 7 Neutrons. Given--- Mass of Ammonia = 1.7 grams. Molecular mass of Ammonia = 17 grams. Number of Atoms = (Mass/Molecular mass)× Avogadro's Number(NA) = (1.7/17)× Avogadro's Number = 0.1× Avogadro's Number = 0.1 Na ∵one atom of Ammonia contains 7 Neutrons.∴, 0.1 Na ---------------------------------- 7× 0.1 Na = 0.7 Na = 0.7 × NaSince Na = 6.022× 10²³Thus, Number of Neutrons = 0.7 × 6.022× 10²³ = 4.2154 × 10²³ Neutrons. |
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