Saved Bookmarks
| 1. |
Number of primary, secondary, tertiary and neo carbons in the following compound respectively are CH_(3) - CH_(2) - overset(overset(CH_(3))(|))(CH) - underset(underset(CH_(3))(|))overset(overset(CH_(3))(|))(C ) - CH_(3) |
|
Answer» 4,2,1,1 |
|