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Number of solutions of equation `sin x.sqrt(8cos^(2)x)=1` in `[0, 2pi]` are |
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Answer» Correct Answer - 4 Number of solutions………. Solutions are possible when `sin x gt 0 i.e.,x epsilon(0, pi)` case I `x epsilon(0, (pi)/(2)], sin2x=(1)/(sqrt(2))` `implies 2x = (pi)/(4), (3pi)/(4) implies x = (pi)/(8), (3pi)/(8)` case II `x in[(pi)/(2), pi], sin2x = (-1)/(sqrt(2))` `implies 2x = (5pi)/(4), (7pi)/(4) implies x = (5pi)/(8), (7pi)/(8)` |
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