Number of unit cells in 4g of X(atomic mass=40). Which crystallises in bcc pattern in `(N_(0)="Avogadro number")`A. 0.1 `N_(A)`B. `2xx0.1N_(A)`C. `(0.1N_(A))/(2)`D. `2xxN_(A)`

Number of unit cells in 4g of X(atomic mass=40). Which crystallises in

1.	Number of unit cells in 4g of X(atomic mass=40). Which crystallises in bcc pattern in `(N_(0)="Avogadro number")`A. 0.1 `N_(A)`B. `2xx0.1N_(A)`C. `(0.1N_(A))/(2)`D. `2xxN_(A)`
Answer» Correct Answer - C 40 g = `N_(A)` atoms 2 atoms form 1 unit cell in bcc crystal `:.0.1xxN_(A)` atom `=(0.1xxN_(A))/(2)` unit cells

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Number of unit cells in 4g of X(atomic mass=40). Which crystallises in bcc pattern in `(N_(0)="Avogadro number")`A. 0.1 `N_(A)`B. `2xx0.1N_(A)`C. `(0.1N_(A))/(2)`D. `2xxN_(A)`

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