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Number of X is randomly selected from the set of odd numbers and Y is randomly selected from the set of even numbers of the set {1,2,3,4,5,6,7}. Let Z = X + Y, then What is P(Z=5) equal to? |
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Answer» Solution :`n(S)=12` `n(E_(1))=12` `P(Z=5)=(n(E_(1)))/(n(S))=(2)/(12)=(1)/(6)` |
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