1.

Number of X is randomly selected from the set of odd numbers and Y is randomly selected from the set of even numbers of the set {1,2,3,4,5,6,7}. Let Z = X + Y, then What is P(Z=10) equal to?

Answer»

<P>0
`1//2`
`1//3`
`1//5`

Solution :`P(Z=10)=(N(E_(2)))/(n(S))=(0)/(12)=(1)/(6)`


Discussion

No Comment Found

Related InterviewSolutions