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o.5 amphere current has been flowing in a circuit for 20 minutes calculate the number of electrons flowing from one end to the another end of the circuit |
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Answer»
GIVEN- I(ELECTRIC current)=0.5A and,. time=20min=20*60=1200s
we know that, I=ne/t e= 1.6*10-19C {CHARGE on one so, 0.5=n*1.6*10-19/1200 n*1.6*10-19= 600 n= 6*100/1.6*10-19 n=3.75*10^21 electrons |
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