1.

o.5 amphere current has been flowing in a circuit for 20 minutes calculate the number of electrons flowing from one end to the another end of the circuit ​

Answer»

GIVEN- I(ELECTRIC current)=0.5A

and,. time=20min=20*60=1200s

we know that, I=ne/t

e= 1.6*10-19C {CHARGE on one

ELECTRON}

so, 0.5=n*1.6*10-19/1200

n*1.6*10-19= 600

n= 6*100/1.6*10-19

n=3.75*10^21 electrons



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