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`O` is a point at the bottom of a rough plane inclined at an angle `alpha` to the horizontal. Coefficient of frictionbetween `AB` is`(Tanalpha)/(2)`and between `BO` is `(3Tanalpha)/(2)`. `B` is the mid–point of `AO`. A block is released from rest at A. Then identify which graphs are correct during motion of block from point `A` to `O` taking direction down the incline plane as positive `(sinalpha=1//5)` : A. B. C. D. |
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Answer» Correct Answer - C For motion between `AB` `ma=mg sin alpha-(tanalpha)/(2) mg cos alpha` `a=(g sinalpha)/(2)` (downward) For motion between `BO` `ma=(3tan alpha)/(2) mg cos alpha-mg sin alpha` `a=(gsinalpha)/(2)` (upward) The velocity increases from zero to maximum value of `B` and then starts decreasing with same rate and finally becomes zero at `O`. |
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