1.

O Mole fraction of the solute in a 1.00 molal aqueoussolution is(1) 1.7700(3) 0.0177AIPMT (Prelims)-2011](2) 0.1770(4) 0.0344

Answer»

Molality = Moles of solute / Mass of solvent in kg

Molality is given as 1Therefore,1 mole of solute is dissolved in 1 kg of water

Moles of solvent = 1000 g / (18 g/mol)= 55.55 mol

Mole fraction of solute = 1 / (1 + 55.5)= 0.017

Mole fraction of solute is 0.017



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