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O2 is evolved by heating KClO3 using MnO2 as a catalystCalculate the number of moles of oxygen present in the above volume and also the number of molecules. |
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Answer» At STP, 22.4 l of a gas = 1 mole 6.72 l = (1 x 6.72)/22.4 = 0.3 moles One mole contains = 6 x 1023 molecules 0.3 mole contains = 6 x 1023 x 0.3 = 1.8 x 1023 molecules 6.72 l of oxygen contains 0.3 moles and hence 1.8 x 1023 molecules. |
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