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Obtain an expression for the expparent frequency of sound for an observer moving towards // away from a stationary source of sound. |
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Answer» Solution :Let v be the velocity of SOUND in still air. Let `v_(0)` be the velocity of an observer. Let `T_(0)` be the TIME associated with observer in moving from 0 to 0. `t_(n+1) - t_(1)= nT_(0)-(nv_(0)T_(0))/( v_(0) +v) = nT_(0)[ (v_(0) + v- v_(0))/(v_(0) + v)]` i.e., `( t_(n+1)-t_(1)) =(nT_(0) v)/( v+ v(0))` Apparent FREQUENCY of sound as heard by the observer `f =( 1)/( T )= ( v+ v_(0))/( T_(0)v)` i.e., `f= f_(0)"" (v+ v_(0))/(v)` Apparent wavelength `lambda = lambda_(0)` For an observer moving away from the SOURCE. `f = f_(0) ""(v-v_(0))/(v) ` and `Delta lambda = 0` |
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