Obtain an expression for total energy of a satellite revolving in circular orbit around a planet .

Obtain an expression for total energy of a satellite revolving in circ

1.	Obtain an expression for total energy of a satellite revolving in circular orbit around a planet .
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :GravitationalP.E. at a point above the surface of the earth at a distance r = R + h is given by P.E. = `(-GM m)/(r)` where 'M' is mass of the earth and m is the mass of the satellite . <br/> kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of satellite = `(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) (GMm)/(r)` <br/> Total energy of satellite = E = PE + KE <br/> Hence E = `(-GMm)/(r) + (1)/(2) (GMm)/(r)` <br/> i.e., `E = - (1)/(2) (GMm)/(r)` <br/> The `-ve` sign <a href="https://interviewquestions.tuteehub.com/tag/indicates-1041501" style="font-weight:bold;" target="_blank" title="Click to know more about INDICATES">INDICATES</a> that the satellite is bounded to the earth .</body></html>