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Obtain Coulomb's law from Gauss's law. |
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Answer» Solution :As SHOWN in figure, consider a POINT charge +q kept at O. A Gaussian surface .S. is shown in figure includes charge q. Consider surface area`vecds` at point E Here, `vecE || vecds` ds and so that `theta =0^(@)` . According to Gauss.s law, `phi =q/epsilon_(0)` `therefore int vecE.vec(ds) = q/epsilon_(0)` `therefore intE.ds COS0^(@) =q/epsilon_(0)[therefore vecE || vecds]` `therefore E=q/(4piepsilon_(0)r^(2))` `therefore F/q =q/(4piepsilon_(0)r^(2))` `therefore F = (Kq.q_(0))/r^(2)` This is Coulomb.s law. |
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