Obtain Eq. (7.38) omega= omega_0 + alphat from first principles.

1.	Obtain Eq. (7.38) omega= omega_0 + alphat from first principles.
Answer» Solution :The ANGULAR acceleration is uniform, hence `(domega)/(dt)=alpha` = constant (i) INTEGRATING this equation, `omega=intalphadt+c` `=alphat+c` (as `alpha` is constant) At `t = 0,ω= ω_(0)` (given) From (i) we GET at `t=0,ω=c=omega_(0)` Thus, `ω = αt + ω_(0)` as required. With the definition of `ω= d θ //dt` we may integrate Eq. (7.38) to get .This derivation and the derivation of Eq. (7.40) is left as an exercise.

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