1.

Obtain the dimensions of linear momentum and surface tension in terms of velocity (v), density (rho) and frequency(nu) as fundamental units.

Answer»


Solution :`V=[LT^(-1)],rho=[ML^(-3)],v=[T^(-1)],p=mv=[MLT^(-1)]=[ML^(-3)][LT^(-1)]^(4)[T^(-1)]^(-3)=rhov^(4)v^(-3)`
Surface tension `=MT^(-2)=[ML^(-3)][LT^(-1)]^(3)[T^(-1)]^(-1)=rhov^(3)v^(-1)`


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