1.

Obtain the dimensions of Planck’s constant.

Answer»

The energy of a photon of frequency v is E = hv, where h is the Planck’s, constant.

∴ [h] = \(\cfrac{[E]}{[v]}\) = \(\cfrac{ML^2T^{-2}}{T^{-1}}\) = ML2 T-1



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