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obtain the equation of hyperbola in each of the following cases: centre at (0,0) conjugate axis along x-axis of length 6 and eccentricity 2. |
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Answer» SOLUTION :Here 2b=6 `IMPLIES` b=3 , c/a=2 or ca=2 We have `a^2+b^2=c^2` or `a^2+9=4a^2` OR `a^2=3` `THEREFORE` EQN of HYPERBOLA is `y^2/a^2-x^2/b^2=1 or `y^2/3-x^2/9=1` |
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