1.

obtain the equation of hyperbola in each of the following cases : foci at (+-4,0) and vertices at (+-2,0).

Answer»

SOLUTION :Here c=4 ,a=2 `THEREFORE` b^2=c^2-a^2=12` `therefore` EQN of the HYPERBOLA is `x^2/a^2+y^2/b^2=1` or `x^2/4-y^2/12=1`


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