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obtain the equation of hyperbola in each of the following cases: centre (1,-2) transverse axis parallel to x-axis of length 6 and conjugate axis of length 10. |
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Answer» Solution :CENTRE (1,-2) transverse axis parallel to x-axisof length 6 conjugate axis of length 10 .`THEREFORE` 2a=6 , 2b=10 `therefore` a=3 , b=5, h=1 , k=-2 `therefore` EQN of the hyperbola `(x-h)^2/a^2-(y-k)^2/b^2=1` or `(x-1)^2/9-(y-2)^2/25=1` |
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