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| 1. |
obtain the equation of hyperbola in each of the following cases: centre at (0,0) transverse axis is along y-axis the distance between the foci is 14 and distance between the vertices is 12. |
| Answer» Solution :Here 2C =14 2a =12 `therefore` c=7, a=6 `therefore` b^2=c^2-a^2=13` `therefore` EQN of the ELLIPSE is `y^2/a62-x^2/b^2=1` or `y^2/36-x^2/13=1` | |