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Obtain the equation of straight lines : Passing through (1,-1) and making an angle 150^@. |
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Answer» SOLUTION :Slope of the line =`tan150^@ = - 1/sqrt3` `therefore` EQUATION of the line `y-y_1 = m(X-x_1)` or, `y+1 = -1/sqrt3 (x-1)` or, `ysqrt3 + sqrt3 = -x + 1` or, `x+ysqrt3 + sqrt3-1 = 0` . |
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