1.

Obtain the equation of straight lines : Passing through (1,-1) and making an angle 150^@.

Answer»

SOLUTION :Slope of the line
=`tan150^@ = - 1/sqrt3`
`therefore` EQUATION of the line
`y-y_1 = m(X-x_1)`
or, `y+1 = -1/sqrt3 (x-1)`
or, `ysqrt3 + sqrt3 = -x + 1`
or, `x+ysqrt3 + sqrt3-1 = 0` .


Discussion

No Comment Found

Related InterviewSolutions