Obtain the equation of the circle for which (3, 4) and (2, -7) are the

1.	Obtain the equation of the circle for which (3, 4) and (2, -7) are the ends of a diameter.
Answer» The equation of a circle with (x₁, y₁) and (x₂, y₂) as end points of a diameter is (x – x₁)(x – x₂) + (y – y₁)(y – y₂) = 0 Here the end points of a diameter are (3, 4) and (2, -7) So equation of the circle is (x – 3 )(x – 2 ) + (y – 4) (y + 7.) = 0 x² + y² – 5x + 37 – 22 = 0

Obtain the equation of the circle for which (3, 4) and (2, -7) are the ends of a diameter.

Answer»

The equation of a circle with (x₁, y₁) and (x₂, y₂) as end points of a diameter is

(x – x₁)(x – x₂) + (y – y₁)(y – y₂) = 0

Here the end points of a diameter are (3, 4) and (2, -7)

So equation of the circle is

(x – 3 )(x – 2 ) + (y – 4) (y + 7.) = 0

x² + y² – 5x + 37 – 22 = 0