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Obtain the formula for the coefficient of performance of carnot engine. |
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Answer» Solution :Efficiency in CYCLIC PROCESS `eta=1-Q_2/Q_1` and efficiency of carnot engine `eta=1-T_2/T_1` `THEREFORE Q_2/Q_1=T_2/T_1 RARR Q_1/Q_2 =T_1/T_2` EXPANDING this `therefore (Q_1-Q_2)/Q_2=(T_1-T_2)/T_2` Reversing ` therefore Q_2/(Q_1-Q_2)=T_2/(T_1-T_2)` But `Q_2/(Q_1-Q_2)` is called coefficient of performance `alpha`. `therefore alpha=T_2/(T_1-T_2)` |
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