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Obtain the relation between equilibrium constant K and K' forward and reverse reaction. |
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Answer» Solution :We write reaction of HI synthesis. Its equilibrium is as under. `H_(2(g)) + I_(2(g)) hArr 2HI_((g))`…(Eq. -i) For this reaction as PER law of chemical equilibrium `K_c` is as follow. `K_c="[HI]"^2/([H_2][I_2])=X` ….(Eq.-ii) At same temperature the reverse reaction-(i) occurs the equilibrium of decomposition of HI reaction is as under. `2HI_((g)) hArr H_(2(g)) +I_(2(g))`.....(Eq.-iii) The equilibrium constant `K._c` at same temp. is , `K._c=([H_2][I_2])/([HI]^2)=1/X`....(Eq.-iv) So, `(K_c)(K._c)=([HI]^2)/([H_2][I_2])xx([H_2][I_2])/([HI]^2)=1` and `K_c=1/(K._c)` ....(RESULT -1) "Equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the reaction in the forward direction." |
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