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Obtain the relation between the units of some physical quantity in two different systems o units. |
Answer» <html><body><p></p>Solution :The unit of work in MKS system is Joule and that in CGS system is erg. <br/> The relation between Joule and erg can be obtained as <a href="https://interviewquestions.tuteehub.com/tag/follows-994526" style="font-weight:bold;" target="_blank" title="Click to know more about FOLLOWS">FOLLOWS</a>. <br/> <a href="https://interviewquestions.tuteehub.com/tag/dimensional-2582799" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONAL">DIMENSIONAL</a> <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> for work, `W=M^(1)L^(2)T^(-2)` <br/> in MKS syste = in CGS system <br/> `m(kg)=10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)` <br/> `L(m)=10^(2) L (cm)` <br/> `T(s)=10^(0)T(s)` <br/> `L^(1)L^(2)T^(-2)=(10^(3)M^(1))(10^(2)L)^(2)(10^(0)T)^(-2)`<br/> `=10^()xx10^(4)M^(1)L^(-2)T^(-2)` <br/> `=10^(7)M^(1)L^(2)T^(-2)` <br/> So, MKS unit of work =`10^(7)` CGS unit of work <br/> `:. 1J=10^(7)` erg</body></html> | |