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Obtain the temperature ragnes for ultraviolet part of radiation of e.m.waves. Use the formulae `lambda_m T=2.9xx10^-3mK`. Take frequency of ultraviolet part of radiations as `8xx10^14Hz` to `5xx10^17Hz`. |
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Answer» The corresponding wavelength to the frequency `8xx10^14Hz` is `lambda_1=c/(v_1)=(3xx10^8)/(8xx10^14)=3.75xx10^-7m` The corresponding wavelength to the frequency `5xx10^17` is `lambda_2=c/(v_2)=(3xx10^8)/(5xx10^17)=6xx10^-10m` As `lambda_mT=2.9xx10^-3 or T=(2.9xx10^-3)/(lambda_m)` For, `lambda_1=3.75xx10^-7m,` `T_1=(2.9xx10^-3)/(3.75xx10^-7)=7.73xx10^3K` For, `lambda_2=6xx10^-10m,` `T_2=(2.9xx10^-3)/(6xx10^-10)=4.83xx10^6K` Temperature range is `7.73xx10^3K to 4.83xx10^6K` |
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