Saved Bookmarks
| 1. |
Obtain the velocity of projected particle executing uniform circular motion. |
|
Answer» SOLUTION :The linear VELOCITY of a particle moving in a circular path of radius A with angular speed `omega` is the radius time to angular velocity. `THEREFORE v= A omega` The DIRECTION of linear velocity of a particle at time t is in the direction of tangent at a point on the circle at that time. According to figure, two matual components of linear velocity `A omega`, component `A omega SIN (omega t+ phi)` in X-axis direction, is the velocity of projection on X-axis of a particle at time t. `therefore v(t)= -A omega sin (omega t+phi)` Direction of v(t) is oppositre to X-axis and it is the isntantaneous velocity of particle executing SHM.
|
|