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Obtain the zeros of the quadratic equation 4x^2+5√2x-3 |
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Answer» Solution: We have polynomial is 4x²+5√2x-3 4x²+5√2x-3=0 a=4 b=5√2 c=-3 D=b²-4ac D=(5√2)²-4x4x(-3) D= 50+48 D=98 Apply Quadratic formula we got two zeros are -b±√D/2a - 5✓2 +- ✓ 50+48/2*4 |
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