InterviewSolution
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InterviewSolution
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Odds in favour of an event A are 2 to 1 and odds in favour of `A cup B` are 3 to 1. Consistant with his information the smallest and largest values for the probability of event B are given byA. `(1)/(6) le P(B) le (1)/(3)`B. `(1)/(3) le P(B) le (1)/(2)`C. `(1)/(12) le P(B) le (3)/(4)`D. none of these |
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Answer» Correct Answer - C We have, `P(A)=(2)/(3),P(A cup B)=(3)/(4)` `therefore P(A cup B)=P(A)+P(B)-P(A cap B)` `implies (3)/(4)=(2)/(3)+P(B)-P(A cap B)` `implies P(A cap B)=P(B)-(1)/(12)` Now, `0 le P (A cap B) le P(A)` `implies 0 le P(B)-(1)/(12) le P(A) implies (1)/(12) le P(B) le (3)/(4)` |
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