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of th ⏠Comp=CH is |
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Answer» This hydrocarbon has both double(ene) and triple(yne) bond hence this hydrocarbon is eneyne. Hence while naming ene is to be placed before yne. Now start numbering the carbon atoms from right to left because triple bond is at terminal position hence first preference goes to it. Now it has 5carbon atoms hence Pent So clubbing it all we get Pent-3-ene-1-yne |
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