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Of the 3 numbers whose average is 112, the first is 3/13 times the sum of other 2. The first number is ________.1). 632). 953). 424). 126 |
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Answer» Let the three number be x, y and z. Of the 3 numbers whose average is 112, the first is 3/13 TIMES the sum of other 2. So, we can WRITE now, x + y + z = 112 × 3 ---- (1) x = (y + z) × (3/13) ⇒ y + z = 13x/3 ---- (2) Substituting the VALUE of eq. (2) in eq. (1) we get, x + (13x/3) = 112 × 3 ⇒ 16x = 112 × 9 ⇒ x = 63 ∴ The first number is 63. |
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