1.

Of the 3 numbers whose average is 112, the first is 3/13 times the sum of other 2. The first number is ________.1). 632). 953). 424). 126

Answer»

Let the three number be x, y and z.

Of the 3 numbers whose average is 112, the first is 3/13 TIMES the sum of other 2.

So, we can WRITE now,

x + y + z = 112 × 3 ---- (1)

x = (y + z) × (3/13)

⇒ y + z = 13x/3 ---- (2)

Substituting the VALUE of eq. (2) in eq. (1) we get,

x + (13x/3) = 112 × 3

⇒ 16x = 112 × 9

⇒ x = 63

∴ The first number is 63.



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