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Of the three numbers, the average of the first number and the second number is 37 more than the average of second number and third number. What is the difference between the first and the third number?1). 742). 733). 374). Cannot be determined |
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Answer» Let the THREE NUMBERS be a, b, C Given the AVERAGE of the ‘a and ‘b’ is 37 more than the average of ‘b’ and ‘c’ ⇒ [(a + b)/2] = 37 + [(b + c)/2] ⇒ [(a + b)/2] = [74 + b + c]/2 ⇒ (a + b) = 74 + b + c ⇒ a - c = 74 ∴ Required Difference = 74 |
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