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of37 Calculatepresenttotaldebno.ofelectronsmethenein |
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Answer» Gram-molecular mass ofmethane(CH4)=12+4=16g.Numberof molecules ofmethanein 0.1mole=0.1×6.02×1023.⇒6.02×1022.One molecules ofmethanehas 6+4=10electronsSo,6.02×1023 molecules ofmethanehave =10×6.02×1022electrons.⇒6.02×1023electrons. |
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