On a frictionless surface, a blockof mass . Mmoving at speed v collides elastically with another blockof same mass M which is intiallyat rest /After collisionthe firstblockmoes at an angle thetato its initial direction and has a speed v/3 The second block's speed after the collision is :

On a frictionless surface, a blockof mass . Mmoving at speed v collide

1.	On a frictionless surface, a blockof mass . Mmoving at speed v collides elastically with another blockof same mass M which is intiallyat rest /After collisionthe firstblockmoes at an angle thetato its initial direction and has a speed v/3 The second block's speed after the collision is :
Answer» `(sqrt(3))/2v` `(2sqrt(2))/3V` `3/4` V `3/(sqrt(2))v` Solution :In elastic collision energy of system remainsconstant . ` :. ` Kinetic energy before collision = kinetic energy after collision ` :. 1/2 mv^(2)+0=1/2m (v/3)^(2) +1/2m(v)^(2)` After collision , v is the SPEED of second block . ` :. v^(2) = (v^(2))/9+(v)^(2)` ` :. (9V^(2)-v^(2))/9 =(v)^(2)` ` :. (8v^(2))/9 = (v)^(2)` ` :. v = (2sqrt(2))/3 v `