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On a new scale of temperature (which is linear) and called the `W` scale. The freezing and boiling points of water are `39^(@)W` and `239^(@)W` respectively. What will be the temperature on the new scale, corresponding to a temperature of `39^(@)C` on the Celsius scale?A. `200^(@)W`B. `139^(@)W`C. `78^(@)W`D. `117^(@)W` |
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Answer» Correct Answer - D `(C)/(100)=(W-39)/(239-39)` `(39)/(100)=(W-39)/(200)` `W=117` |
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