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On a photosensitive material, when frequency of incident radiation is increased by 30% kinetic energy of emitted photoelectrons increases from `0.4 eV` to `0.9 eV`. The work function of the surface isA. 1eVB. 1.267eVC. 1.4eVD. 1.8eV |
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Answer» Correct Answer - B `hv=0.4+W_(0) .....(i)` `1.3 hv=0.9+W_(0) .....(ii)` (ii)-1.3 (i) gives `0.3 W_(0)=0.9-1.3 (0.4)` `therefore W_(0)=(0.38)/(0.3)=1.267eV` |
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