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On a semi-circle with AB as diameter, a point C is taken, so that m(∠CAB) = 30°. Find m(∠ACB) and m(∠ABC). |
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Answer» Given: m(∠CAB)= 30° To Find: m(∠ACB) and m(∠ABC). Now, ∠ACB = 90° (Angle in semi-circle) Now, In △ABC, by angle sum property: ∠CAB + ∠ACB + ∠ABC = 180° 30° + 90° + ∠ABC = 180° ∠ABC = 60° Answer: ∠ACB = 90° and ∠ABC = 60° |
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