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On analysing an impure sample of sodium chloride, the percentage of chlorine was found to be 45.5. What is the percentage of pure sodium chloride in the sample ? |
Answer» Molecular mass of pure NaCl = Atomic mass of Na + Atomic mass of Cl `= 23 + 35.5 = 58.5` u Percentage of chlorine in pure NaCl `= ((35.5 "u"))/((58.5 "u"))xx100=60.6` Now, if chlorine is 60.6 parts, NaCl = 100 parts if chlorine is 45.5 parts, NaCl `= ((45.5 "u"))/((60.6 "u")) xx100 = 75` Thus, percentage of pure NaCl = 75 %. |
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