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On analysing an impure sample of sodium chloride, the percentage of chlorine was found to be 45.5. What is the percentage of pure sodium chloride in the sample ?

Answer» Molecular mass of pure NaCl = Atomic mass of Na + Atomic mass of Cl
`= 23 + 35.5 = 58.5` u
Percentage of chlorine in pure NaCl `= ((35.5 "u"))/((58.5 "u"))xx100=60.6`
Now, if chlorine is 60.6 parts, NaCl = 100 parts
if chlorine is 45.5 parts, NaCl `= ((45.5 "u"))/((60.6 "u")) xx100 = 75`
Thus, percentage of pure NaCl = 75 %.


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