On boiling 1 litre N/5HCl the volume of the aqueous solution decreases to 250 mL During this reaction 3.65 g of HCl is removed from solution, then the concerntration of resulting solution becomes : [HCl = 36.5 g "mol"^(-1)]

On boiling 1 litre N/5HCl the volume of the aqueous solution decreases

1.	On boiling 1 litre N/5HCl the volume of the aqueous solution decreases to 250 mL During this reaction 3.65 g of HCl is removed from solution, then the concerntration of resulting solution becomes : [HCl = 36.5 g "mol"^(-1)]
Answer» `N/20` `N/10` `N/2.5` `N/5` Solution :`qm//L = "Normality" xx "G. equivalent wt."` `= N/5 xx36.5 =(36.5)/(5)` `= 7.3 ` gm HCl in `1L N/5` HCl HCl left after boiling `=7.3` g initial HCl `- 3.65` g removed HCl `=3.65g` HCl left in 250 mL solution `N=("wt. of solute" xx 1000)/("gm." - "equivalent wt." xx "volume(mL)")` `= (3.65xx1000)/(36.5xx250)= (10)/(15) = (1)/(1.5) = (N)/(2.5)`