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On complete combustion of substance in 0.22 g oxygen, 0.9 g of waterandoasCalculate the mass of this substance.0.9 g ofwater and 0.44 gotco,s poos |
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Answer» Let the mass of the substance be x grams. According to the law of conservation of mass, sum of masses of reactants = sum of masses of products=> X + 0.22 = 0.9+0.44=> X = 0.22+0.9=> X = 1.12 grams Please hit the like button if this helped you thank you!but you have written x=0.22+0.9,but where is 0.44 |
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